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Popular >

|2(x-1)+4|<= 8

Solution

∣ 2 (x - 1) + 4 ∣ \leq 8

Solution

- 5 \leq x \leq 3

+1

Interval Notation

[- 5, 3]

Solution steps

∣ 2 (x - 1) + 4 ∣ \leq 8

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 8 \leq 2 (x - 1) + 4 \leq 8

2 (x - 1) + 4 \geq - 8 and 2 (x - 1) + 4 \leq 8

x \geq - 5 and x \leq 3

Merge Overlapping Intervals

- 5 \leq x \leq 3

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x^{5} - y^{5}

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Frequently Asked Questions (FAQ)

What is |2(x-1)+4|<= 8 ?
The solution to |2(x-1)+4|<= 8 is -5<= x<= 3