What are the solutions to the equation x(-2x-13)=-1 ?

The solutions to the equation x(-2x-13)=-1 are x=-(13+sqrt(177))/4 ,x=(sqrt(177)-13)/4

Find the zeros of x(-2x-13)=-1

The zeros of x(-2x-13)=-1 are x=-(13+sqrt(177))/4 ,x=(sqrt(177)-13)/4

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x (- 2 x - 13) = - 1

x = - \frac{13 + 177}{4}, x = \frac{177 - 13}{4}

Decimal Notation

x = - 6.57603 \dots, x = 0.07603 \dots

Solution steps

x (- 2 x - 13) = - 1

Expand

x (- 2 x - 13) : - 2 x^{2} - 13 x

- 2 x^{2} - 13 x = - 1

Move

1

to the left side

- 2 x^{2} - 13 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 ( - 2 ) \cdot 1}{2 ( - 2 )}

(- 13)^{2} - 4 (- 2) \cdot 1 = 177

x_{1, 2} = \frac{- ( - 13 ) \pm 177}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 177}{2 ( - 2 )}, x_{2} = \frac{- ( - 13 ) - 177}{2 ( - 2 )}

x = \frac{- ( - 13 ) + 177}{2 ( - 2 )} : - \frac{13 + 177}{4}

x = \frac{- ( - 13 ) - 177}{2 ( - 2 )} : \frac{177 - 13}{4}

The solutions to the quadratic equation are:

x = - \frac{13 + 177}{4}, x = \frac{177 - 13}{4}

x^{2} - 8 x + 21 = 0

4 y = y^{2} - 12

(a + b)^{2} - (a - b)^{2}

3 p - 2 c^{3} - 3 c^{3} p + 2

\frac{4 x ^{2}}{25} - \frac{1}{25} = 0

What are the solutions to the equation x(-2x-13)=-1 ?
The solutions to the equation x(-2x-13)=-1 are x=-(13+sqrt(177))/4 ,x=(sqrt(177)-13)/4
Find the zeros of x(-2x-13)=-1
The zeros of x(-2x-13)=-1 are x=-(13+sqrt(177))/4 ,x=(sqrt(177)-13)/4