What are the solutions to the equation 14^2+x^2=28^2 ?

The solutions to the equation 14^2+x^2=28^2 are x=14sqrt(3),x=-14sqrt(3)

Find the zeros of 14^2+x^2=28^2

The zeros of 14^2+x^2=28^2 are x=14sqrt(3),x=-14sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1 4^{2} + x^{2} = 2 8^{2}

x = 143, x = - 143

Decimal Notation

x = 24.24871 \dots, x = - 24.24871 \dots

Solution steps

1 4^{2} + x^{2} = 2 8^{2}

Move

1 4^{2}

to the right side

x^{2} = 588

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 588, x = - 588

588 = 143

- 588 = - 143

x = 143, x = - 143

w^{3} + 125

5 x - 3 = 2

23 + 18 u = - 21 + 14 u

∣ 3 x - 4 ∣ < 2

1 - 4 ∣ 8 + 8 m ∣ > - 63

What are the solutions to the equation 14^2+x^2=28^2 ?
The solutions to the equation 14^2+x^2=28^2 are x=14sqrt(3),x=-14sqrt(3)
Find the zeros of 14^2+x^2=28^2
The zeros of 14^2+x^2=28^2 are x=14sqrt(3),x=-14sqrt(3)