What are the solutions to the equation -3x^2-5x-8=0 ?

The solutions to the equation -3x^2-5x-8=0 are x=-5/6-i(sqrt(71))/6 ,x=-5/6+i(sqrt(71))/6

Find the zeros of -3x^2-5x-8=0

The zeros of -3x^2-5x-8=0 are x=-5/6-i(sqrt(71))/6 ,x=-5/6+i(sqrt(71))/6

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- 3 x^{2} - 5 x - 8 = 0

x = - \frac{5}{6} - i \frac{71}{6}, x = - \frac{5}{6} + i \frac{71}{6}

Solution steps

- 3 x^{2} - 5 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 3 ) ( - 8 )}{2 ( - 3 )}

Simplify

(- 5)^{2} - 4 (- 3) (- 8) : 71 i

x_{1, 2} = \frac{- ( - 5 ) \pm 71 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 71 i}{2 ( - 3 )}, x_{2} = \frac{- ( - 5 ) - 71 i}{2 ( - 3 )}

x = \frac{- ( - 5 ) + 71 i}{2 ( - 3 )} : - \frac{5}{6} - i \frac{71}{6}

x = \frac{- ( - 5 ) - 71 i}{2 ( - 3 )} : - \frac{5}{6} + i \frac{71}{6}

The solutions to the quadratic equation are:

x = - \frac{5}{6} - i \frac{71}{6}, x = - \frac{5}{6} + i \frac{71}{6}

∣ q + 3 ∣ \leq 5

x 3 = 12

7 a^{- 5} b^{3}

\frac{7 + i}{3 - i}

- 11 (\frac{3}{2}) (0.12 (- 12))

What are the solutions to the equation -3x^2-5x-8=0 ?
The solutions to the equation -3x^2-5x-8=0 are x=-5/6-i(sqrt(71))/6 ,x=-5/6+i(sqrt(71))/6
Find the zeros of -3x^2-5x-8=0
The zeros of -3x^2-5x-8=0 are x=-5/6-i(sqrt(71))/6 ,x=-5/6+i(sqrt(71))/6