What are the solutions to the equation 4x^2+3=-7x ?

The solutions to the equation 4x^2+3=-7x are x=-3/4 ,x=-1

Find the zeros of 4x^2+3=-7x

The zeros of 4x^2+3=-7x are x=-3/4 ,x=-1

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4 x^{2} + 3 = - 7 x

x = - \frac{3}{4}, x = - 1

Decimal Notation

x = - 0.75, x = - 1

Solution steps

4 x^{2} + 3 = - 7 x

Move

7 x

to the left side

4 x^{2} + 3 + 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 7 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

7^{2} - 4 \cdot 4 \cdot 3 = 1

x_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 7 + 1}{2 \cdot 4}, x_{2} = \frac{- 7 - 1}{2 \cdot 4}

x = \frac{- 7 + 1}{2 \cdot 4} : - \frac{3}{4}

x = \frac{- 7 - 1}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

x = - \frac{3}{4}, x = - 1

4 x^{2} - 9 x

a = 60000 (1 + \frac{0.06}{4})^{4 \cdot 5}

3 (1 - 3 v) = 2 (2 + 3 v)

5 x^{2} + 21 x + 4

(x + 2)^{2} (x - 2)^{2}

What are the solutions to the equation 4x^2+3=-7x ?
The solutions to the equation 4x^2+3=-7x are x=-3/4 ,x=-1
Find the zeros of 4x^2+3=-7x
The zeros of 4x^2+3=-7x are x=-3/4 ,x=-1