What are the solutions to the equation -x^2-13x-2=-3x+3 ?

The solutions to the equation -x^2-13x-2=-3x+3 are x=-5-2sqrt(5),x=-5+2sqrt(5)

Find the zeros of -x^2-13x-2=-3x+3

The zeros of -x^2-13x-2=-3x+3 are x=-5-2sqrt(5),x=-5+2sqrt(5)

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- x^{2} - 13 x - 2 = - 3 x + 3

x = - 5 - 25, x = - 5 + 25

Decimal Notation

x = - 9.47213 \dots, x = - 0.52786 \dots

Solution steps

- x^{2} - 13 x - 2 = - 3 x + 3

Move

3

to the left side

- x^{2} - 13 x - 5 = - 3 x

Move

3 x

to the left side

- x^{2} - 10 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 ( - 1 ) ( - 5 )}{2 ( - 1 )}

(- 10)^{2} - 4 (- 1) (- 5) = 45

x_{1, 2} = \frac{- ( - 10 ) \pm 4 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 4 5}{2 ( - 1 )}, x_{2} = \frac{- ( - 10 ) - 4 5}{2 ( - 1 )}

x = \frac{- ( - 10 ) + 4 5}{2 ( - 1 )} : - 5 - 25

x = \frac{- ( - 10 ) - 4 5}{2 ( - 1 )} : - 5 + 25

The solutions to the quadratic equation are:

x = - 5 - 25, x = - 5 + 25

h + 1 > 3

\frac{x}{4} + \frac{x}{3} = 7

y, x + y = 3

- 1^{2} - x + 2 = 0

\frac{4}{15}

What are the solutions to the equation -x^2-13x-2=-3x+3 ?
The solutions to the equation -x^2-13x-2=-3x+3 are x=-5-2sqrt(5),x=-5+2sqrt(5)
Find the zeros of -x^2-13x-2=-3x+3
The zeros of -x^2-13x-2=-3x+3 are x=-5-2sqrt(5),x=-5+2sqrt(5)