What are the solutions to the equation (2x-3)*(3x+8)=0 ?

The solutions to the equation (2x-3)*(3x+8)=0 are x= 3/2 ,x=-8/3

Find the zeros of (2x-3)*(3x+8)=0

The zeros of (2x-3)*(3x+8)=0 are x= 3/2 ,x=-8/3

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(2 x - 3) \cdot (3 x + 8) = 0

x = \frac{3}{2}, x = - \frac{8}{3}

Decimal Notation

x = 1.5, x = - 2.66666 \dots

Solution steps

(2 x - 3) (3 x + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 3 = 0 or 3 x + 8 = 0

Solve

2 x - 3 = 0 : x = \frac{3}{2}

Solve

3 x + 8 = 0 : x = - \frac{8}{3}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - \frac{8}{3}

lo g_{0.5} (2)

- \frac{3}{4} - \frac{7}{8}

∣ - 7 + 5 ∣

\frac{6 ^{6}}{6}

∣ 7 x ∣ = 4 - x

What are the solutions to the equation (2x-3)*(3x+8)=0 ?
The solutions to the equation (2x-3)*(3x+8)=0 are x= 3/2 ,x=-8/3
Find the zeros of (2x-3)*(3x+8)=0
The zeros of (2x-3)*(3x+8)=0 are x= 3/2 ,x=-8/3