What are the solutions to the equation 2x^2-9x-26=0 ?

The solutions to the equation 2x^2-9x-26=0 are x= 13/2 ,x=-2

Find the zeros of 2x^2-9x-26=0

The zeros of 2x^2-9x-26=0 are x= 13/2 ,x=-2

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2 x^{2} - 9 x - 26 = 0

x = \frac{13}{2}, x = - 2

Decimal Notation

x = 6.5, x = - 2

Solution steps

2 x^{2} - 9 x - 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 ( - 26 )}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 (- 26) = 17

x_{1, 2} = \frac{- ( - 9 ) \pm 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 17}{2 \cdot 2}, x_{2} = \frac{- ( - 9 ) - 17}{2 \cdot 2}

x = \frac{- ( - 9 ) + 17}{2 \cdot 2} : \frac{13}{2}

x = \frac{- ( - 9 ) - 17}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = \frac{13}{2}, x = - 2

\frac{( 25 + 4 )}{3} + 25 = 20

(x + 8)^{2} = 2 x + 15

∣ 2 - y ∣ = y - 2

10000

(\frac{1}{4} x^{2} - \frac{1}{6} y^{2})^{2}

What are the solutions to the equation 2x^2-9x-26=0 ?
The solutions to the equation 2x^2-9x-26=0 are x= 13/2 ,x=-2
Find the zeros of 2x^2-9x-26=0
The zeros of 2x^2-9x-26=0 are x= 13/2 ,x=-2