What is (2^n+4^n)/(2^{2n)(1+2^n)} ?

The solution to (2^n+4^n)/(2^{2n)(1+2^n)} is (2^n+4^n)/(4^n(1+2^n))

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simplify (2^n+4^n)/(2^{2n)(1+2^n)}

simplify

\frac{2 ^{n} + 4 ^{n}}{2 ^{2 n} ( 1 + 2 ^{n} )}

\frac{2 ^{n} + 4 ^{n}}{4 ^{n} ( 1 + 2 ^{n} )}

Solution steps

\frac{2 ^{n} + 4 ^{n}}{2 ^{2 n} ( 1 + 2 ^{n} )}

2^{2 n} = 4^{n}

= \frac{2 ^{n} + 4 ^{n}}{4 ^{n} ( 2 ^{n} + 1 )}

2 x^{4} + 3 x^{3} + 2 x^{2} + 3 x

- 22 > 5 x - 7 \geq - 3

2 (- 1)^{4}

n^{2} + 34 n + 225

\frac{1}{1 + ( \frac{y}{x} ) ^{2}} \cdot \frac{1}{x}

What is (2^n+4^n)/(2^{2n)(1+2^n)} ?
The solution to (2^n+4^n)/(2^{2n)(1+2^n)} is (2^n+4^n)/(4^n(1+2^n))