What are the solutions to the equation x^2+10x=-4 ?

The solutions to the equation x^2+10x=-4 are x=-5+sqrt(21),x=-5-sqrt(21)

Find the zeros of x^2+10x=-4

The zeros of x^2+10x=-4 are x=-5+sqrt(21),x=-5-sqrt(21)

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x^{2} + 10 x = - 4

x = - 5 + 21, x = - 5 - 21

Solution steps

x^{2} + 10 x = - 4

Move

4

to the left side

x^{2} + 10 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 4 = 221

x_{1, 2} = \frac{- 10 \pm 2 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 21}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 21}{2 \cdot 1}

x = \frac{- 10 + 2 21}{2 \cdot 1} : - 5 + 21

x = \frac{- 10 - 2 21}{2 \cdot 1} : - 5 - 21

The solutions to the quadratic equation are:

x = - 5 + 21, x = - 5 - 21

(\frac{5}{7})^{4}

u^{2} - 57 u - 58

36 t^{2} + 36 t + 9

x^{3} - x^{2} + x - 1

What are the solutions to the equation x^2+10x=-4 ?
The solutions to the equation x^2+10x=-4 are x=-5+sqrt(21),x=-5-sqrt(21)
Find the zeros of x^2+10x=-4
The zeros of x^2+10x=-4 are x=-5+sqrt(21),x=-5-sqrt(21)