What are the solutions to the equation 2x^2+16x-59=9 ?

The solutions to the equation 2x^2+16x-59=9 are x=-4+5sqrt(2),x=-4-5sqrt(2)

Find the zeros of 2x^2+16x-59=9

The zeros of 2x^2+16x-59=9 are x=-4+5sqrt(2),x=-4-5sqrt(2)

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2 x^{2} + 16 x - 59 = 9

x = - 4 + 52, x = - 4 - 52

Decimal Notation

x = 3.07106 \dots, x = - 11.07106 \dots

Solution steps

2 x^{2} + 16 x - 59 = 9

Move

9

to the left side

2 x^{2} + 16 x - 68 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 2 ( - 68 )}{2 \cdot 2}

1 6^{2} - 4 \cdot 2 (- 68) = 202

x_{1, 2} = \frac{- 16 \pm 20 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 16 + 20 2}{2 \cdot 2}, x_{2} = \frac{- 16 - 20 2}{2 \cdot 2}

x = \frac{- 16 + 20 2}{2 \cdot 2} : - 4 + 52

x = \frac{- 16 - 20 2}{2 \cdot 2} : - 4 - 52

The solutions to the quadratic equation are:

x = - 4 + 52, x = - 4 - 52

x^{2} + 4 x = 15

10 m^{2} + 9 = 499

x^{2} = 36

\frac{1}{7} \cdot 7

10 + \frac{g}{- 9} > 12

What are the solutions to the equation 2x^2+16x-59=9 ?
The solutions to the equation 2x^2+16x-59=9 are x=-4+5sqrt(2),x=-4-5sqrt(2)
Find the zeros of 2x^2+16x-59=9
The zeros of 2x^2+16x-59=9 are x=-4+5sqrt(2),x=-4-5sqrt(2)