What are the solutions to the equation 2x^2-2x+2=0 ?

The solutions to the equation 2x^2-2x+2=0 are x= 1/2+i(sqrt(3))/2 ,x= 1/2-i(sqrt(3))/2

Find the zeros of 2x^2-2x+2=0

The zeros of 2x^2-2x+2=0 are x= 1/2+i(sqrt(3))/2 ,x= 1/2-i(sqrt(3))/2

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2 x^{2} - 2 x + 2 = 0

x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

Solution steps

2 x^{2} - 2 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

Simplify

(- 2)^{2} - 4 \cdot 2 \cdot 2 : 23 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 3 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 3 i}{2 \cdot 2}, x_{2} = \frac{- ( - 2 ) - 2 3 i}{2 \cdot 2}

x = \frac{- ( - 2 ) + 2 3 i}{2 \cdot 2} : \frac{1}{2} + i \frac{3}{2}

x = \frac{- ( - 2 ) - 2 3 i}{2 \cdot 2} : \frac{1}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

4 x - 7 + x = 10 - 3 x - 1

\frac{5}{12} + \frac{11}{18}

\frac{- 1}{x - 6} < \frac{2}{9 - x}

(2 + 2)^{2}

16 x^{2} - 12 x + 4 = 0

What are the solutions to the equation 2x^2-2x+2=0 ?
The solutions to the equation 2x^2-2x+2=0 are x= 1/2+i(sqrt(3))/2 ,x= 1/2-i(sqrt(3))/2
Find the zeros of 2x^2-2x+2=0
The zeros of 2x^2-2x+2=0 are x= 1/2+i(sqrt(3))/2 ,x= 1/2-i(sqrt(3))/2