What are the solutions to the equation x^2=-8+6x ?

The solutions to the equation x^2=-8+6x are x=4,x=2

Find the zeros of x^2=-8+6x

The zeros of x^2=-8+6x are x=4,x=2

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x^{2} = - 8 + 6 x

x = 4, x = 2

Solution steps

x^{2} = - 8 + 6 x

Move

6 x

to the left side

x^{2} - 6 x = - 8

Move

8

to the left side

x^{2} - 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 8 = 2

x_{1, 2} = \frac{- ( - 6 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2}{2 \cdot 1} : 4

x = \frac{- ( - 6 ) - 2}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 4, x = 2

\frac{g}{3} - 2 = 1

\frac{y}{6} = \frac{6}{9}

(\frac{- 6 ( r + 4 r ^{2} ) + 9 r ^{2} + 6 r}{3 r})^{2}

5 x = 1

(3 - 1)^{3}

What are the solutions to the equation x^2=-8+6x ?
The solutions to the equation x^2=-8+6x are x=4,x=2
Find the zeros of x^2=-8+6x
The zeros of x^2=-8+6x are x=4,x=2