What are the solutions to the equation (2w-3)w=14 ?

The solutions to the equation (2w-3)w=14 are w= 7/2 ,w=-2

Find the zeros of (2w-3)w=14

The zeros of (2w-3)w=14 are w= 7/2 ,w=-2

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(2 w - 3) w = 14

w = \frac{7}{2}, w = - 2

Decimal Notation

w = 3.5, w = - 2

Solution steps

(2 w - 3) w = 14

Expand

(2 w - 3) w : 2 w^{2} - 3 w

2 w^{2} - 3 w = 14

Move

14

to the left side

2 w^{2} - 3 w - 14 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 14 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 14) = 11

w_{1, 2} = \frac{- ( - 3 ) \pm 11}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- ( - 3 ) + 11}{2 \cdot 2}, w_{2} = \frac{- ( - 3 ) - 11}{2 \cdot 2}

w = \frac{- ( - 3 ) + 11}{2 \cdot 2} : \frac{7}{2}

w = \frac{- ( - 3 ) - 11}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

w = \frac{7}{2}, w = - 2

\frac{x}{4} = 1 - \frac{3 x}{2}

e^{3.2}

a x - a y + b x - b y

- 5144

50 - 10 x = 20

What are the solutions to the equation (2w-3)w=14 ?
The solutions to the equation (2w-3)w=14 are w= 7/2 ,w=-2
Find the zeros of (2w-3)w=14
The zeros of (2w-3)w=14 are w= 7/2 ,w=-2