What are the solutions to the equation 7x^2+x-2=4 ?

The solutions to the equation 7x^2+x-2=4 are x= 6/7 ,x=-1

Find the zeros of 7x^2+x-2=4

The zeros of 7x^2+x-2=4 are x= 6/7 ,x=-1

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7 x^{2} + x - 2 = 4

x = \frac{6}{7}, x = - 1

Decimal Notation

x = 0.85714 \dots, x = - 1

Solution steps

7 x^{2} + x - 2 = 4

Move

4

to the left side

7 x^{2} + x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 7 ( - 6 )}{2 \cdot 7}

1^{2} - 4 \cdot 7 (- 6) = 13

x_{1, 2} = \frac{- 1 \pm 13}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 1 + 13}{2 \cdot 7}, x_{2} = \frac{- 1 - 13}{2 \cdot 7}

x = \frac{- 1 + 13}{2 \cdot 7} : \frac{6}{7}

x = \frac{- 1 - 13}{2 \cdot 7} : - 1

The solutions to the quadratic equation are:

x = \frac{6}{7}, x = - 1

3 x^{2} - 10 x = 0

\frac{7}{4} + \frac{1}{2} x = \frac{13}{2} - \frac{7}{4} x

\frac{π}{2} + \frac{3 π}{4}

30 + 3 x^{5}

\frac{1}{2} ab c - \frac{1}{4} a^{2} b^{2} c^{2}

What are the solutions to the equation 7x^2+x-2=4 ?
The solutions to the equation 7x^2+x-2=4 are x= 6/7 ,x=-1
Find the zeros of 7x^2+x-2=4
The zeros of 7x^2+x-2=4 are x= 6/7 ,x=-1