What are the solutions to the equation x^2+1/6 x+1=0 ?

The solutions to the equation x^2+1/6 x+1=0 are x=-1/12+i(sqrt(143))/(12),x=-1/12-i(sqrt(143))/(12)

Find the zeros of x^2+1/6 x+1=0

The zeros of x^2+1/6 x+1=0 are x=-1/12+i(sqrt(143))/(12),x=-1/12-i(sqrt(143))/(12)

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x^{2} + \frac{1}{6} x + 1 = 0

x = - \frac{1}{12} + i \frac{143}{12}, x = - \frac{1}{12} - i \frac{143}{12}

Solution steps

x^{2} + \frac{1}{6} x + 1 = 0

Multiply both sides by

6

6 x^{2} + x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 6 \cdot 6}{2 \cdot 6}

Simplify

1^{2} - 4 \cdot 6 \cdot 6 : 143 i

x_{1, 2} = \frac{- 1 \pm 143 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 1 + 143 i}{2 \cdot 6}, x_{2} = \frac{- 1 - 143 i}{2 \cdot 6}

x = \frac{- 1 + 143 i}{2 \cdot 6} : - \frac{1}{12} + i \frac{143}{12}

x = \frac{- 1 - 143 i}{2 \cdot 6} : - \frac{1}{12} - i \frac{143}{12}

The solutions to the quadratic equation are:

x = - \frac{1}{12} + i \frac{143}{12}, x = - \frac{1}{12} - i \frac{143}{12}

m r + n s - n r - m s

1 0^{2} + 2 0^{2} = 3 0^{2}

4 x + 4 + 9 x + 18 = 12 (x + 2)

x^{2} + 19 x + 60

20 + 20 y < - 20

What are the solutions to the equation x^2+1/6 x+1=0 ?
The solutions to the equation x^2+1/6 x+1=0 are x=-1/12+i(sqrt(143))/(12),x=-1/12-i(sqrt(143))/(12)
Find the zeros of x^2+1/6 x+1=0
The zeros of x^2+1/6 x+1=0 are x=-1/12+i(sqrt(143))/(12),x=-1/12-i(sqrt(143))/(12)