What is 5x^2+15x>= 3x^2+8 ?

The solution to 5x^2+15x>= 3x^2+8 is x = 1/2

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5x^2+15x>= 3x^2+8

5 x^{2} + 15 x \geq 3 x^{2} + 8

x \leq - 8 or x \geq \frac{1}{2}

Interval Notation

(- \infty, - 8] \cup [\frac{1}{2}, \infty)

Decimal Notation

x \leq - 8 or x \geq 0.5

Solution steps

5 x^{2} + 15 x \geq 3 x^{2} + 8

Rewrite in standard form

2 x^{2} + 15 x - 8 \geq 0

Factor

2 x^{2} + 15 x - 8 : (2 x - 1) (x + 8)

(2 x - 1) (x + 8) \geq 0

Identify the intervals

x \leq - 8 or x \geq \frac{1}{2}

f = \frac{1}{3} \cdot 4^{4}

\frac{4 x}{x ^{2} - 9} \leq - 1

5 u^{2} - 14 u + 8 = 0

9 k^{2} - (5 m - 1)^{2}

\frac{2 x - 3}{4} - \frac{3 + 2 x}{9} = 2 - \frac{x + 1}{6}

What is 5x^2+15x>= 3x^2+8 ?
The solution to 5x^2+15x>= 3x^2+8 is x<=-8\lor x>= 1/2