What are the solutions to the equation 5(x+2)^2=20 ?

The solutions to the equation 5(x+2)^2=20 are x=0,x=-4

Find the zeros of 5(x+2)^2=20

The zeros of 5(x+2)^2=20 are x=0,x=-4

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5 (x + 2)^{2} = 20

x = 0, x = - 4

Solution steps

5 (x + 2)^{2} = 20

Divide both sides by

5

(x + 2)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 4 : x = 0

Solve

x + 2 = - 4 : x = - 4

The solutions to the quadratic equation are:

x = 0, x = - 4

\frac{5}{9} (- 13 - 32)

32 x^{3} - 500

6 x - 8 (1 - x) - (10 x + 4) = 0

- 10 x^{2} - 5 t + 75

7 x^{3} - x^{2} + 7 x - 1

What are the solutions to the equation 5(x+2)^2=20 ?
The solutions to the equation 5(x+2)^2=20 are x=0,x=-4
Find the zeros of 5(x+2)^2=20
The zeros of 5(x+2)^2=20 are x=0,x=-4