What are the solutions to the equation m^2-16m+64=0 ?

The solutions to the equation m^2-16m+64=0 are m=8

Find the zeros of m^2-16m+64=0

The zeros of m^2-16m+64=0 are m=8

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m^{2} - 16 m + 64 = 0

m = 8

Solution steps

m^{2} - 16 m + 64 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 64}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 64 = 0

m_{1, 2} = \frac{- ( - 16 ) \pm 0}{2 \cdot 1}

m = \frac{- ( - 16 )}{2 \cdot 1}

\frac{- ( - 16 )}{2 \cdot 1} = 8

m = 8

The solution to the quadratic equation is:

m = 8

x - 6 \geq 15

\frac{3 ^{- 2}}{3 ^{- 4}}

16.8 \geq v - 3

\frac{x + 3}{x - 2} > 3

k^{2} - 9 = 0

What are the solutions to the equation m^2-16m+64=0 ?
The solutions to the equation m^2-16m+64=0 are m=8
Find the zeros of m^2-16m+64=0
The zeros of m^2-16m+64=0 are m=8