What are the solutions to the equation x^2-24x+62=-9x+6 ?

The solutions to the equation x^2-24x+62=-9x+6 are x=8,x=7

Find the zeros of x^2-24x+62=-9x+6

The zeros of x^2-24x+62=-9x+6 are x=8,x=7

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x^{2} - 24 x + 62 = - 9 x + 6

x = 8, x = 7

Solution steps

x^{2} - 24 x + 62 = - 9 x + 6

Move

6

to the left side

x^{2} - 24 x + 56 = - 9 x

Move

9 x

to the left side

x^{2} - 15 x + 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 56}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 56 = 1

x_{1, 2} = \frac{- ( - 15 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 1}{2 \cdot 1}

x = \frac{- ( - 15 ) + 1}{2 \cdot 1} : 8

x = \frac{- ( - 15 ) - 1}{2 \cdot 1} : 7

The solutions to the quadratic equation are:

x = 8, x = 7

x^{3} - 8 x^{2} + 12 x \leq 0

6 x^{2} - 4 x - 2 \leq 9 x^{2} - 15 x + 6

(4 x^{- 4})^{- \frac{1}{2}}

1 + \frac{21000000}{49000000}

5 x = 1 - 3 x^{2}

What are the solutions to the equation x^2-24x+62=-9x+6 ?
The solutions to the equation x^2-24x+62=-9x+6 are x=8,x=7
Find the zeros of x^2-24x+62=-9x+6
The zeros of x^2-24x+62=-9x+6 are x=8,x=7