What are the solutions to the equation x^2-8x+16=4 ?

The solutions to the equation x^2-8x+16=4 are x=6,x=2

Find the zeros of x^2-8x+16=4

The zeros of x^2-8x+16=4 are x=6,x=2

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x^{2} - 8 x + 16 = 4

x = 6, x = 2

Solution steps

x^{2} - 8 x + 16 = 4

Move

4

to the left side

x^{2} - 8 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 12 = 4

x_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 4}{2 \cdot 1}

x = \frac{- ( - 8 ) + 4}{2 \cdot 1} : 6

x = \frac{- ( - 8 ) - 4}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 6, x = 2

\frac{4}{3} π (7)^{3}

\frac{2 ( 5 )}{( 5 + 1 ) ^{2}}

3 a^{2} + 8 ab + 5 b^{2}

3 x + 2 < 20

\frac{2 i ^{8} + 2 i ^{- 7}}{i ^{11} + 1}

What are the solutions to the equation x^2-8x+16=4 ?
The solutions to the equation x^2-8x+16=4 are x=6,x=2
Find the zeros of x^2-8x+16=4
The zeros of x^2-8x+16=4 are x=6,x=2