What are the solutions to the equation x^2-6x+10=5 ?

The solutions to the equation x^2-6x+10=5 are x=5,x=1

Find the zeros of x^2-6x+10=5

The zeros of x^2-6x+10=5 are x=5,x=1

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x^{2} - 6 x + 10 = 5

x = 5, x = 1

Solution steps

x^{2} - 6 x + 10 = 5

Move

5

to the left side

x^{2} - 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 5 = 4

x_{1, 2} = \frac{- ( - 6 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 4}{2 \cdot 1}

x = \frac{- ( - 6 ) + 4}{2 \cdot 1} : 5

x = \frac{- ( - 6 ) - 4}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 5, x = 1

(- 2) \frac{2 + 3 i}{1 + i} + (2 - i)^{2}

2 x + 1 < 1

3 x^{2} + x - 14 = 0

2 x^{2} - x = - 1

4 a^{2} - 9 x^{4}

What are the solutions to the equation x^2-6x+10=5 ?
The solutions to the equation x^2-6x+10=5 are x=5,x=1
Find the zeros of x^2-6x+10=5
The zeros of x^2-6x+10=5 are x=5,x=1