What are the solutions to the equation 0=36t-0.8t^2 ?

The solutions to the equation 0=36t-0.8t^2 are t=0,t=45

Find the zeros of 0=36t-0.8t^2

The zeros of 0=36t-0.8t^2 are t=0,t=45

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0 = 36 t - 0.8 t^{2}

t = 0, t = 45

Solution steps

0 = 36 t - 0.8 t^{2}

Multiply both sides by

10

0 = 360 t - 8 t^{2}

Switch sides

360 t - 8 t^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 8 t^{2} + 360 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 360 \pm 36 0 ^{2} - 4 ( - 8 ) \cdot 0}{2 ( - 8 )}

36 0^{2} - 4 (- 8) \cdot 0 = 360

t_{1, 2} = \frac{- 360 \pm 360}{2 ( - 8 )}

Separate the solutions

t_{1} = \frac{- 360 + 360}{2 ( - 8 )}, t_{2} = \frac{- 360 - 360}{2 ( - 8 )}

t = \frac{- 360 + 360}{2 ( - 8 )} : 0

t = \frac{- 360 - 360}{2 ( - 8 )} : 45

The solutions to the quadratic equation are:

t = 0, t = 45

5 x - 2 (2 x - 1) = 6

6 r k^{2} + 16 r k + 8 r

e^{3 y} > 6

\frac{( \frac{3 x}{y} )}{( \frac{2 x}{7} )}

1 + 2 (x + 5) = x + 3 (x - 1)

What are the solutions to the equation 0=36t-0.8t^2 ?
The solutions to the equation 0=36t-0.8t^2 are t=0,t=45
Find the zeros of 0=36t-0.8t^2
The zeros of 0=36t-0.8t^2 are t=0,t=45