What are the solutions to the equation x^2-8x+3=0 ?

The solutions to the equation x^2-8x+3=0 are x=4+sqrt(13),x=4-sqrt(13)

Find the zeros of x^2-8x+3=0

The zeros of x^2-8x+3=0 are x=4+sqrt(13),x=4-sqrt(13)

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x^{2} - 8 x + 3 = 0

x = 4 + 13, x = 4 - 13

Decimal Notation

x = 7.60555 \dots, x = 0.39444 \dots

Solution steps

x^{2} - 8 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 3 = 213

x_{1, 2} = \frac{- ( - 8 ) \pm 2 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 13}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 13}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 13}{2 \cdot 1} : 4 + 13

x = \frac{- ( - 8 ) - 2 13}{2 \cdot 1} : 4 - 13

The solutions to the quadratic equation are:

x = 4 + 13, x = 4 - 13

∣ x + 5 ∣ < 9

\frac{π}{4} - π

5 x - 1 \leq 3 + 3 x

(6 + 43)^{2}

- \frac{0.8 ( 19 )}{( 0.01 ( 19 ) ^{2} + 1 ) ^{2}}

What are the solutions to the equation x^2-8x+3=0 ?
The solutions to the equation x^2-8x+3=0 are x=4+sqrt(13),x=4-sqrt(13)
Find the zeros of x^2-8x+3=0
The zeros of x^2-8x+3=0 are x=4+sqrt(13),x=4-sqrt(13)