What is factor 15x^2+4x-4 ?

The solution to factor 15x^2+4x-4 is (5x-2)(3x+2)

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factor 15x^2+4x-4

factor

15 x^{2} + 4 x - 4

(5 x - 2) (3 x + 2)

Solution steps

15 x^{2} + 4 x - 4

Break the expression into groups

= (15 x^{2} - 6 x) + (10 x - 4)

Factor out

3 x

from

15 x^{2} - 6 x : 3 x (5 x - 2)

Factor out

2

from

10 x - 4 : 2 (5 x - 2)

= 3 x (5 x - 2) + 2 (5 x - 2)

Factor out common term

5 x - 2

= (5 x - 2) (3 x + 2)

(- 87 + i) + (- 5 + 20 i)

(\frac{a ^{2}}{b})^{5} (\frac{a ^{3} b ^{2}}{c ^{3}})^{3}

\frac{1}{1 + \frac{1}{1 + \frac{1}{3}}}

\frac{3 + 5 x}{5} = \frac{4 - x}{7}

(\frac{256}{81})^{\frac{1}{4}}