What are the solutions to the equation 16x^2+9=5 ?

The solutions to the equation 16x^2+9=5 are x= 1/2 i,x=-1/2 i

Find the zeros of 16x^2+9=5

The zeros of 16x^2+9=5 are x= 1/2 i,x=-1/2 i

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16 x^{2} + 9 = 5

x = \frac{1}{2} i, x = - \frac{1}{2} i

Solution steps

16 x^{2} + 9 = 5

Move

9

to the right side

16 x^{2} = - 4

Divide both sides by

16

x^{2} = - \frac{1}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{4}, x = - - \frac{1}{4}

- \frac{1}{4} = \frac{1}{2} i

- - \frac{1}{4} = - \frac{1}{2} i

x = \frac{1}{2} i, x = - \frac{1}{2} i

6 = 3 t - 3

5 x^{2} + 7 x - 34 = 0

lo g_{3} (\frac{1}{81}) = - 4

q^{2} = 25

3 x + 3 \leq - 6

What are the solutions to the equation 16x^2+9=5 ?
The solutions to the equation 16x^2+9=5 are x= 1/2 i,x=-1/2 i
Find the zeros of 16x^2+9=5
The zeros of 16x^2+9=5 are x= 1/2 i,x=-1/2 i