What are the solutions to the equation 6x^2+6x-5=0 ?

The solutions to the equation 6x^2+6x-5=0 are x=(-3+sqrt(39))/6 ,x=-(3+sqrt(39))/6

Find the zeros of 6x^2+6x-5=0

The zeros of 6x^2+6x-5=0 are x=(-3+sqrt(39))/6 ,x=-(3+sqrt(39))/6

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6 x^{2} + 6 x - 5 = 0

x = \frac{- 3 + 39}{6}, x = - \frac{3 + 39}{6}

Decimal Notation

x = 0.54083 \dots, x = - 1.54083 \dots

Solution steps

6 x^{2} + 6 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 6 ( - 5 )}{2 \cdot 6}

6^{2} - 4 \cdot 6 (- 5) = 239

x_{1, 2} = \frac{- 6 \pm 2 39}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 6 + 2 39}{2 \cdot 6}, x_{2} = \frac{- 6 - 2 39}{2 \cdot 6}

x = \frac{- 6 + 2 39}{2 \cdot 6} : \frac{- 3 + 39}{6}

x = \frac{- 6 - 2 39}{2 \cdot 6} : - \frac{3 + 39}{6}

The solutions to the quadratic equation are:

x = \frac{- 3 + 39}{6}, x = - \frac{3 + 39}{6}

5 x^{2} + 6 x = 2

\frac{5 ^{3}}{3}

9 x + 11 \geq 8 x + 10

24 x^{3} y^{2} - 30 x^{2} y^{3} + 12 x^{2} y^{4}

5 z = 4

What are the solutions to the equation 6x^2+6x-5=0 ?
The solutions to the equation 6x^2+6x-5=0 are x=(-3+sqrt(39))/6 ,x=-(3+sqrt(39))/6
Find the zeros of 6x^2+6x-5=0
The zeros of 6x^2+6x-5=0 are x=(-3+sqrt(39))/6 ,x=-(3+sqrt(39))/6