What are the solutions to the equation -3x^2+6x+5=0 ?

The solutions to the equation -3x^2+6x+5=0 are x=-(-3+2sqrt(6))/3 ,x=(3+2sqrt(6))/3

Find the zeros of -3x^2+6x+5=0

The zeros of -3x^2+6x+5=0 are x=-(-3+2sqrt(6))/3 ,x=(3+2sqrt(6))/3

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- 3 x^{2} + 6 x + 5 = 0

x = - \frac{- 3 + 2 6}{3}, x = \frac{3 + 2 6}{3}

Decimal Notation

x = - 0.63299 \dots, x = 2.63299 \dots

Solution steps

- 3 x^{2} + 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) \cdot 5}{2 ( - 3 )}

6^{2} - 4 (- 3) \cdot 5 = 46

x_{1, 2} = \frac{- 6 \pm 4 6}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 6 + 4 6}{2 ( - 3 )}, x_{2} = \frac{- 6 - 4 6}{2 ( - 3 )}

x = \frac{- 6 + 4 6}{2 ( - 3 )} : - \frac{- 3 + 2 6}{3}

x = \frac{- 6 - 4 6}{2 ( - 3 )} : \frac{3 + 2 6}{3}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 2 6}{3}, x = \frac{3 + 2 6}{3}

4 x - 5 \geq 3

∣ 4 - 2 x ∣ \geq - 6

x y - x^{2} y^{4}

\frac{9}{5} (5) + 32

4 x^{2} + 11 x - 69

What are the solutions to the equation -3x^2+6x+5=0 ?
The solutions to the equation -3x^2+6x+5=0 are x=-(-3+2sqrt(6))/3 ,x=(3+2sqrt(6))/3
Find the zeros of -3x^2+6x+5=0
The zeros of -3x^2+6x+5=0 are x=-(-3+2sqrt(6))/3 ,x=(3+2sqrt(6))/3