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Popular >

|2(x-1)+8|<= 6

Solution

∣ 2 (x - 1) + 8 ∣ \leq 6

Solution

- 6 \leq x \leq 0

+1

Interval Notation

[- 6, 0]

Solution steps

∣ 2 (x - 1) + 8 ∣ \leq 6

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 6 \leq 2 (x - 1) + 8 \leq 6

2 (x - 1) + 8 \geq - 6 and 2 (x - 1) + 8 \leq 6

x \geq - 6 and x \leq 0

Merge Overlapping Intervals

- 6 \leq x \leq 0

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Frequently Asked Questions (FAQ)

What is |2(x-1)+8|<= 6 ?
The solution to |2(x-1)+8|<= 6 is -6<= x<= 0