What is the answer to 0=(-32)/(81(x^2-x-20)) ?

The answer to 0=(-32)/(81(x^2-x-20)) is No Solution

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0=(-32)/(81(x^2-x-20))

0 = \frac{- 32}{81 ( x ^{2} - x - 20 )}

No Solution

Solution steps

0 = \frac{- 32}{81 ( x ^{2} - x - 20 )}

Simplify

\frac{- 32}{81 ( x ^{2} - x - 20 )} : - \frac{32}{81 ( x ^{2} - x - 20 )}

0 = - \frac{32}{81 ( x ^{2} - x - 20 )}

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

0 = 32

The sides are not equal

No Solution

x^{2} + 7 x - 16 = 0

- \frac{1}{3} + \frac{1}{6}

3 - 50

3 (1 - \frac{5}{2} x) + 4 x = 5

2 (2)^{3}

What is the answer to 0=(-32)/(81(x^2-x-20)) ?
The answer to 0=(-32)/(81(x^2-x-20)) is No Solution
Solve for x: 0=(-32)/(81(x^2-x-20))
The solution is No Solution