What are the solutions to the equation 5^2+b^2=10^2 ?

The solutions to the equation 5^2+b^2=10^2 are b=5sqrt(3),b=-5sqrt(3)

Find the zeros of 5^2+b^2=10^2

The zeros of 5^2+b^2=10^2 are b=5sqrt(3),b=-5sqrt(3)

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5^{2} + b^{2} = 1 0^{2}

b = 53, b = - 53

Decimal Notation

b = 8.66025 \dots, b = - 8.66025 \dots

Solution steps

5^{2} + b^{2} = 1 0^{2}

Move

5^{2}

to the right side

b^{2} = 75

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 75, b = - 75

75 = 53

- 75 = - 53

b = 53, b = - 53

\frac{4}{6}

- 48 a^{2} b^{2} - 56 a^{3} b - 56 a^{5} b

5 p^{2} - 9 p - 2 = 0

12 - 3 y < 27

\frac{10 + 3 p - p ^{2}}{25 - p ^{2}}

What are the solutions to the equation 5^2+b^2=10^2 ?
The solutions to the equation 5^2+b^2=10^2 are b=5sqrt(3),b=-5sqrt(3)
Find the zeros of 5^2+b^2=10^2
The zeros of 5^2+b^2=10^2 are b=5sqrt(3),b=-5sqrt(3)