What are the solutions to the equation 3r^2-48=0 ?

The solutions to the equation 3r^2-48=0 are r=4,r=-4

Find the zeros of 3r^2-48=0

The zeros of 3r^2-48=0 are r=4,r=-4

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3 r^{2} - 48 = 0

r = 4, r = - 4

Solution steps

3 r^{2} - 48 = 0

Move

48

to the right side

3 r^{2} = 48

Divide both sides by

3

r^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = 16, r = - 16

16 = 4

- 16 = - 4

r = 4, r = - 4

- 6 x - 5 + 9 x = 3 x - 5 + 3

3 \cdot (x - 6) = x + 2

2 x^{2} + 9 = 11 x^{2}

1 - x^{2} = 4 - 4 x

10 x - 3 - 3 x^{2}

What are the solutions to the equation 3r^2-48=0 ?
The solutions to the equation 3r^2-48=0 are r=4,r=-4
Find the zeros of 3r^2-48=0
The zeros of 3r^2-48=0 are r=4,r=-4