What are the solutions to the equation 4x^2-8x=-19 ?

The solutions to the equation 4x^2-8x=-19 are x=1+i(sqrt(15))/2 ,x=1-i(sqrt(15))/2

Find the zeros of 4x^2-8x=-19

The zeros of 4x^2-8x=-19 are x=1+i(sqrt(15))/2 ,x=1-i(sqrt(15))/2

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4 x^{2} - 8 x = - 19

x = 1 + i \frac{15}{2}, x = 1 - i \frac{15}{2}

Solution steps

4 x^{2} - 8 x = - 19

Move

19

to the left side

4 x^{2} - 8 x + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 \cdot 19}{2 \cdot 4}

Simplify

(- 8)^{2} - 4 \cdot 4 \cdot 19 : 415 i

x_{1, 2} = \frac{- ( - 8 ) \pm 4 15 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 15 i}{2 \cdot 4}, x_{2} = \frac{- ( - 8 ) - 4 15 i}{2 \cdot 4}

x = \frac{- ( - 8 ) + 4 15 i}{2 \cdot 4} : 1 + i \frac{15}{2}

x = \frac{- ( - 8 ) - 4 15 i}{2 \cdot 4} : 1 - i \frac{15}{2}

The solutions to the quadratic equation are:

x = 1 + i \frac{15}{2}, x = 1 - i \frac{15}{2}

16 m^{2} - 96 m + 176

5 s^{2} - 26 s = 24

x^{3} y^{3} + 8

2 (5 x + 2) = 50

4 x^{2} - 16 x + 64

What are the solutions to the equation 4x^2-8x=-19 ?
The solutions to the equation 4x^2-8x=-19 are x=1+i(sqrt(15))/2 ,x=1-i(sqrt(15))/2
Find the zeros of 4x^2-8x=-19
The zeros of 4x^2-8x=-19 are x=1+i(sqrt(15))/2 ,x=1-i(sqrt(15))/2