What are the solutions to the equation t^2+7t-2=0 ?

The solutions to the equation t^2+7t-2=0 are t=(-7+sqrt(57))/2 ,t=(-7-sqrt(57))/2

Find the zeros of t^2+7t-2=0

The zeros of t^2+7t-2=0 are t=(-7+sqrt(57))/2 ,t=(-7-sqrt(57))/2

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t^{2} + 7 t - 2 = 0

t = \frac{- 7 + 57}{2}, t = \frac{- 7 - 57}{2}

Solution steps

t^{2} + 7 t - 2 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 2) = 57

t_{1, 2} = \frac{- 7 \pm 57}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- 7 + 57}{2 \cdot 1}, t_{2} = \frac{- 7 - 57}{2 \cdot 1}

t = \frac{- 7 + 57}{2 \cdot 1} : \frac{- 7 + 57}{2}

t = \frac{- 7 - 57}{2 \cdot 1} : \frac{- 7 - 57}{2}

The solutions to the quadratic equation are:

t = \frac{- 7 + 57}{2}, t = \frac{- 7 - 57}{2}

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What are the solutions to the equation t^2+7t-2=0 ?
The solutions to the equation t^2+7t-2=0 are t=(-7+sqrt(57))/2 ,t=(-7-sqrt(57))/2
Find the zeros of t^2+7t-2=0
The zeros of t^2+7t-2=0 are t=(-7+sqrt(57))/2 ,t=(-7-sqrt(57))/2