What are the solutions to the equation (x+7)^2-49=0 ?

The solutions to the equation (x+7)^2-49=0 are x=0,x=-14

Find the zeros of (x+7)^2-49=0

The zeros of (x+7)^2-49=0 are x=0,x=-14

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(x + 7)^{2} - 49 = 0

x = 0, x = - 14

Solution steps

(x + 7)^{2} - 49 = 0

Move

49

to the right side

(x + 7)^{2} = 49

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = 49 : x = 0

Solve

x + 7 = - 49 : x = - 14

The solutions to the quadratic equation are:

x = 0, x = - 14

- 0.0055238774 = (- 7) (x) + (32) (x)^{2}

3 (m - 1) = m + 9

\frac{( \frac{5}{4} )}{2}

\frac{3 ( k ^{5} ) ^{2}}{- 4 k ^{- 4}}

7 (5 x + 8) = 12 - (x + 4)

What are the solutions to the equation (x+7)^2-49=0 ?
The solutions to the equation (x+7)^2-49=0 are x=0,x=-14
Find the zeros of (x+7)^2-49=0
The zeros of (x+7)^2-49=0 are x=0,x=-14