What are the solutions to the equation x^2+x-5/3 =0 ?

The solutions to the equation x^2+x-5/3 =0 are x=(-3+sqrt(69))/6 ,x=(-3-sqrt(69))/6

Find the zeros of x^2+x-5/3 =0

The zeros of x^2+x-5/3 =0 are x=(-3+sqrt(69))/6 ,x=(-3-sqrt(69))/6

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x^{2} + x - \frac{5}{3} = 0

x = \frac{- 3 + 69}{6}, x = \frac{- 3 - 69}{6}

Solution steps

x^{2} + x - \frac{5}{3} = 0

Multiply both sides by

3

3 x^{2} + 3 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

3^{2} - 4 \cdot 3 (- 5) = 69

x_{1, 2} = \frac{- 3 \pm 69}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 3 + 69}{2 \cdot 3}, x_{2} = \frac{- 3 - 69}{2 \cdot 3}

x = \frac{- 3 + 69}{2 \cdot 3} : \frac{- 3 + 69}{6}

x = \frac{- 3 - 69}{2 \cdot 3} : \frac{- 3 - 69}{6}

The solutions to the quadratic equation are:

x = \frac{- 3 + 69}{6}, x = \frac{- 3 - 69}{6}

9 h^{3} - 6 h

\frac{x}{2} - \frac{x}{3} = \frac{1}{6} (x - \frac{3}{2}) + x

9 a^{2} - b^{2}

8 \cdot 1 0^{- 4}

\frac{3 ^{10}}{3 ^{2}}

What are the solutions to the equation x^2+x-5/3 =0 ?
The solutions to the equation x^2+x-5/3 =0 are x=(-3+sqrt(69))/6 ,x=(-3-sqrt(69))/6
Find the zeros of x^2+x-5/3 =0
The zeros of x^2+x-5/3 =0 are x=(-3+sqrt(69))/6 ,x=(-3-sqrt(69))/6