What are the solutions to the equation x^2-8x+35=0 ?

The solutions to the equation x^2-8x+35=0 are x=4+sqrt(19)i,x=4-sqrt(19)i

Find the zeros of x^2-8x+35=0

The zeros of x^2-8x+35=0 are x=4+sqrt(19)i,x=4-sqrt(19)i

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x^{2} - 8 x + 35 = 0

x = 4 + 19 i, x = 4 - 19 i

Solution steps

x^{2} - 8 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 35}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 35 : 219 i

x_{1, 2} = \frac{- ( - 8 ) \pm 2 19 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 19 i}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 19 i}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 19 i}{2 \cdot 1} : 4 + 19 i

x = \frac{- ( - 8 ) - 2 19 i}{2 \cdot 1} : 4 - 19 i

The solutions to the quadratic equation are:

x = 4 + 19 i, x = 4 - 19 i

10 x + 2 = 7

x^{2} + 6 x - 6 = 10

- 3.95 > h - 6.95

(1 + \frac{1}{2})^{2}

\frac{9 2}{2} = x 2

What are the solutions to the equation x^2-8x+35=0 ?
The solutions to the equation x^2-8x+35=0 are x=4+sqrt(19)i,x=4-sqrt(19)i
Find the zeros of x^2-8x+35=0
The zeros of x^2-8x+35=0 are x=4+sqrt(19)i,x=4-sqrt(19)i