What are the solutions to the equation (8x+1)^2-(8x+1)-12=0 ?

The solutions to the equation (8x+1)^2-(8x+1)-12=0 are x= 3/8 ,x=-1/2

Find the zeros of (8x+1)^2-(8x+1)-12=0

The zeros of (8x+1)^2-(8x+1)-12=0 are x= 3/8 ,x=-1/2

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(8 x + 1)^{2} - (8 x + 1) - 12 = 0

x = \frac{3}{8}, x = - \frac{1}{2}

Decimal Notation

x = 0.375, x = - 0.5

Solution steps

(8 x + 1)^{2} - (8 x + 1) - 12 = 0

Expand

(8 x + 1)^{2} - (8 x + 1) - 12 : 64 x^{2} + 8 x - 12

64 x^{2} + 8 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 64 ( - 12 )}{2 \cdot 64}

8^{2} - 4 \cdot 64 (- 12) = 56

x_{1, 2} = \frac{- 8 \pm 56}{2 \cdot 64}

Separate the solutions

x_{1} = \frac{- 8 + 56}{2 \cdot 64}, x_{2} = \frac{- 8 - 56}{2 \cdot 64}

x = \frac{- 8 + 56}{2 \cdot 64} : \frac{3}{8}

x = \frac{- 8 - 56}{2 \cdot 64} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{3}{8}, x = - \frac{1}{2}

\frac{3 - x}{x - 4} \leq 2

h + 1.5 = 8.4

\frac{5}{2} \cdot \frac{8}{20}

\frac{4}{2 i}

2 \cdot 5

What are the solutions to the equation (8x+1)^2-(8x+1)-12=0 ?
The solutions to the equation (8x+1)^2-(8x+1)-12=0 are x= 3/8 ,x=-1/2
Find the zeros of (8x+1)^2-(8x+1)-12=0
The zeros of (8x+1)^2-(8x+1)-12=0 are x= 3/8 ,x=-1/2