What is 6(x^2+1)-(2x-4)(3x+2)<= 3(5x+21) ?

The solution to 6(x^2+1)-(2x-4)(3x+2) =-7

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6(x^2+1)-(2x-4)(3x+2)<= 3(5x+21)

6 (x^{2} + 1) - (2 x - 4) (3 x + 2) \leq 3 (5 x + 21)

x \geq - 7

Solution steps

6 (x^{2} + 1) - (2 x - 4) (3 x + 2) \leq 3 (5 x + 21)

Rewrite in standard form

- x - 7 \leq 0

Move

7

to the right side

- x \leq 7

Multiply both sides by

- 1

x \geq - 7

141

(x + h)^{\frac{3}{2}}

20 x^{3} y^{4} - 52 x^{4} y^{3}

4 ∣ x - 5 ∣ = 20

0.5 x^{2} - x = 0

What is 6(x^2+1)-(2x-4)(3x+2)<= 3(5x+21) ?
The solution to 6(x^2+1)-(2x-4)(3x+2)<= 3(5x+21) is x>=-7