What is (\sqrt[3]{-5})/(40^{1/3)} ?

The solution to (\sqrt[3]{-5})/(40^{1/3)} is -1/2

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simplify (\sqrt[3]{-5})/(40^{1/3)}

simplify

- \frac{1}{2}

Solution steps

Apply radical rule:

n

is odd

Factor

4 0^{\frac{1}{3}} : 5^{\frac{1}{3}} \cdot 8^{\frac{1}{3}}

Apply radical rule:

= \frac{- 5 ^{\frac{1}{3}}}{5 ^{\frac{1}{3}} \cdot 8 ^{\frac{1}{3}}}

Apply the fraction rule:

\frac{a}{a} = 1

\frac{5 ^{\frac{1}{3}}}{5 ^{\frac{1}{3}}} = 1

= \frac{- 1}{8 ^{\frac{1}{3}}}

\frac{- 1}{8 ^{\frac{1}{3}}} = - \frac{1}{2}

= - \frac{1}{2}

\frac{1}{2} x + 3 < 4 x - 7

(5 a - 3 b)^{2} - 25 a^{2}

- 2 (3 y - 6) + 4 (5 y - 8) = 92

\frac{5 + 3}{2 - 3}

4 x^{2} - 15 x - 25

What is (\sqrt[3]{-5})/(40^{1/3)} ?
The solution to (\sqrt[3]{-5})/(40^{1/3)} is -1/2