What are the solutions to the equation 4x^2+12x+25=0 ?

The solutions to the equation 4x^2+12x+25=0 are x=-3/2+2i,x=-3/2-2i

Find the zeros of 4x^2+12x+25=0

The zeros of 4x^2+12x+25=0 are x=-3/2+2i,x=-3/2-2i

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4 x^{2} + 12 x + 25 = 0

x = - \frac{3}{2} + 2 i, x = - \frac{3}{2} - 2 i

Solution steps

4 x^{2} + 12 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

Simplify

1 2^{2} - 4 \cdot 4 \cdot 25 : 16 i

x_{1, 2} = \frac{- 12 \pm 16 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 12 + 16 i}{2 \cdot 4}, x_{2} = \frac{- 12 - 16 i}{2 \cdot 4}

x = \frac{- 12 + 16 i}{2 \cdot 4} : - \frac{3}{2} + 2 i

x = \frac{- 12 - 16 i}{2 \cdot 4} : - \frac{3}{2} - 2 i

The solutions to the quadratic equation are:

x = - \frac{3}{2} + 2 i, x = - \frac{3}{2} - 2 i

\frac{m}{- 14} \leq - 4

4 h^{6} + 14 h^{5} - 12 h^{4} - 42 h^{3}

\frac{1}{4} = \frac{y}{12}

y^{2} - 2 y + 1 = 0

3 x - x + 4 = - 4

What are the solutions to the equation 4x^2+12x+25=0 ?
The solutions to the equation 4x^2+12x+25=0 are x=-3/2+2i,x=-3/2-2i
Find the zeros of 4x^2+12x+25=0
The zeros of 4x^2+12x+25=0 are x=-3/2+2i,x=-3/2-2i