What are the solutions to the equation (x+3)x-7(x+3)=0 ?

The solutions to the equation (x+3)x-7(x+3)=0 are x=7,x=-3

Find the zeros of (x+3)x-7(x+3)=0

The zeros of (x+3)x-7(x+3)=0 are x=7,x=-3

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(x + 3) x - 7 (x + 3) = 0

x = 7, x = - 3

Solution steps

(x + 3) x - 7 (x + 3) = 0

Expand

(x + 3) x - 7 (x + 3) : x^{2} - 4 x - 21

x^{2} - 4 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 21 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 21) = 10

x_{1, 2} = \frac{- ( - 4 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 10}{2 \cdot 1}

x = \frac{- ( - 4 ) + 10}{2 \cdot 1} : 7

x = \frac{- ( - 4 ) - 10}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 7, x = - 3

(\frac{1}{6})^{- 4}

2 x - 7 = 17

x^{2} = - 7 x + 18

5 x - 4 = 0

\frac{2 i}{2}

What are the solutions to the equation (x+3)x-7(x+3)=0 ?
The solutions to the equation (x+3)x-7(x+3)=0 are x=7,x=-3
Find the zeros of (x+3)x-7(x+3)=0
The zeros of (x+3)x-7(x+3)=0 are x=7,x=-3