What is (x-1-2i)(x-1+2i) ?

The solution to (x-1-2i)(x-1+2i) is x^2-2x+5

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simplify (x-1-2i)(x-1+2i)

simplify

(x - 1 - 2 i) (x - 1 + 2 i)

x^{2} - 2 x + 5

Solution steps

(x - 1 - 2 i) (x - 1 + 2 i)

Rewrite

x - 1 - 2 i

in standard complex form:

(x - 1) - 2 i

Rewrite

x - 1 + 2 i

in standard complex form:

(x - 1) + 2 i

= ((x - 1) - 2 i) ((x - 1) + 2 i)

Apply complex arithmetic rule:

(a + bi) (a - bi) = a^{2} + b^{2}

= (x - 1)^{2} + (- 2)^{2}

Simplify

(x - 1)^{2} + (- 2)^{2} : x^{2} - 2 x + 5

= x^{2} - 2 x + 5

6 \cdot 6

ln (400)

9 \leq 3 x + 4

\frac{a}{11.9} = - 3.5