What is factor (3z^2-13z+4)/(z^4-2z^3-8z^2) ?

The solution to factor (3z^2-13z+4)/(z^4-2z^3-8z^2) is (3z-1)/(z^2(z+2))

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factor (3z^2-13z+4)/(z^4-2z^3-8z^2)

factor

\frac{3 z ^{2} - 13 z + 4}{z ^{4} - 2 z ^{3} - 8 z ^{2}}

\frac{3 z - 1}{z ^{2} ( z + 2 )}

Solution steps

\frac{3 z ^{2} - 13 z + 4}{z ^{4} - 2 z ^{3} - 8 z ^{2}}

Factor

3 z^{2} - 13 z + 4 : (3 z - 1) (z - 4)

= \frac{( 3 z - 1 ) ( z - 4 )}{z ^{4} - 2 z ^{3} - 8 z ^{2}}

Factor

z^{4} - 2 z^{3} - 8 z^{2} : z^{2} (z + 2) (z - 4)

= \frac{( 3 z - 1 ) ( z - 4 )}{z ^{2} ( z + 2 ) ( z - 4 )}

Cancel the common factor:

z - 4

= \frac{3 z - 1}{z ^{2} ( z + 2 )}

9 x^{7} y^{5} - 3 x^{2} y^{6}

3 x^{2} - 42 x + 147

z + 3 (z + 7) = - 5

4 x^{2} = 9 x

- \frac{1}{3} - 1

What is factor (3z^2-13z+4)/(z^4-2z^3-8z^2) ?
The solution to factor (3z^2-13z+4)/(z^4-2z^3-8z^2) is (3z-1)/(z^2(z+2))