What are the solutions to the equation 12x^2+17x+6=0 ?

The solutions to the equation 12x^2+17x+6=0 are x=-2/3 ,x=-3/4

Find the zeros of 12x^2+17x+6=0

The zeros of 12x^2+17x+6=0 are x=-2/3 ,x=-3/4

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12 x^{2} + 17 x + 6 = 0

x = - \frac{2}{3}, x = - \frac{3}{4}

Solution steps

12 x^{2} + 17 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 12 \cdot 6}{2 \cdot 12}

1 7^{2} - 4 \cdot 12 \cdot 6 = 1

x_{1, 2} = \frac{- 17 \pm 1}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 17 + 1}{2 \cdot 12}, x_{2} = \frac{- 17 - 1}{2 \cdot 12}

x = \frac{- 17 + 1}{2 \cdot 12} : - \frac{2}{3}

x = \frac{- 17 - 1}{2 \cdot 12} : - \frac{3}{4}

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = - \frac{3}{4}

\frac{1}{x} \geq \frac{1}{x + 3}

\frac{4}{3} (3)

\frac{21 !}{3 ! ( 21 - 3 ) !}

\frac{3}{8} + \frac{1}{2}

2 < x^{2} + 2 x + 2 \leq 10

What are the solutions to the equation 12x^2+17x+6=0 ?
The solutions to the equation 12x^2+17x+6=0 are x=-2/3 ,x=-3/4
Find the zeros of 12x^2+17x+6=0
The zeros of 12x^2+17x+6=0 are x=-2/3 ,x=-3/4