What is factor 4y^2+y-5 ?

The solution to factor 4y^2+y-5 is (y-1)(4y+5)

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factor 4y^2+y-5

factor

4 y^{2} + y - 5

(y - 1) (4 y + 5)

Solution steps

4 y^{2} + y - 5

Break the expression into groups

= (4 y^{2} - 4 y) + (5 y - 5)

Factor out

4 y

from

4 y^{2} - 4 y : 4 y (y - 1)

Factor out

5

from

5 y - 5 : 5 (y - 1)

= 4 y (y - 1) + 5 (y - 1)

Factor out common term

y - 1

= (y - 1) (4 y + 5)

928

x^{4} - x^{2} - 56

7 (B + 3) + 2 B

(\frac{x ^{- 1} y ^{0}}{2 x y ^{0}})^{- 3}

\frac{1}{3} (2 x - 1) = 1