What are the solutions to the equation 4x^2+5x=2 ?

The solutions to the equation 4x^2+5x=2 are x=(-5+sqrt(57))/8 ,x=(-5-sqrt(57))/8

Find the zeros of 4x^2+5x=2

The zeros of 4x^2+5x=2 are x=(-5+sqrt(57))/8 ,x=(-5-sqrt(57))/8

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4 x^{2} + 5 x = 2

x = \frac{- 5 + 57}{8}, x = \frac{- 5 - 57}{8}

Decimal Notation

x = 0.31872 \dots, x = - 1.56872 \dots

Solution steps

4 x^{2} + 5 x = 2

Move

2

to the left side

4 x^{2} + 5 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

5^{2} - 4 \cdot 4 (- 2) = 57

x_{1, 2} = \frac{- 5 \pm 57}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 5 + 57}{2 \cdot 4}, x_{2} = \frac{- 5 - 57}{2 \cdot 4}

x = \frac{- 5 + 57}{2 \cdot 4} : \frac{- 5 + 57}{8}

x = \frac{- 5 - 57}{2 \cdot 4} : \frac{- 5 - 57}{8}

The solutions to the quadratic equation are:

x = \frac{- 5 + 57}{8}, x = \frac{- 5 - 57}{8}

∣ x - 8 ∣ < 1

5 x - 2 \geq 68

(\frac{16}{625})^{\frac{1}{4}}

2 x^{2} + 12 x - 18 = 0

3^{- x} > 6^{- x}

What are the solutions to the equation 4x^2+5x=2 ?
The solutions to the equation 4x^2+5x=2 are x=(-5+sqrt(57))/8 ,x=(-5-sqrt(57))/8
Find the zeros of 4x^2+5x=2
The zeros of 4x^2+5x=2 are x=(-5+sqrt(57))/8 ,x=(-5-sqrt(57))/8