What are the solutions to the equation 208t-16t^2=0 ?

The solutions to the equation 208t-16t^2=0 are t=0,t=13

Find the zeros of 208t-16t^2=0

The zeros of 208t-16t^2=0 are t=0,t=13

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208 t - 16 t^{2} = 0

t = 0, t = 13

Solution steps

208 t - 16 t^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 t^{2} + 208 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 208 \pm 20 8 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

20 8^{2} - 4 (- 16) \cdot 0 = 208

t_{1, 2} = \frac{- 208 \pm 208}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 208 + 208}{2 ( - 16 )}, t_{2} = \frac{- 208 - 208}{2 ( - 16 )}

t = \frac{- 208 + 208}{2 ( - 16 )} : 0

t = \frac{- 208 - 208}{2 ( - 16 )} : 13

The solutions to the quadratic equation are:

t = 0, t = 13

72 = 9 x

14 = y - 10

π 4^{2}

\frac{a ^{3} + 1}{a ^{4} - a ^{3} + a - 1}

5 x^{2} - 11 x - 12

What are the solutions to the equation 208t-16t^2=0 ?
The solutions to the equation 208t-16t^2=0 are t=0,t=13
Find the zeros of 208t-16t^2=0
The zeros of 208t-16t^2=0 are t=0,t=13