What are the solutions to the equation -x^2+x+4=0 ?

The solutions to the equation -x^2+x+4=0 are x=-(-1+sqrt(17))/2 ,x=(1+sqrt(17))/2

Find the zeros of -x^2+x+4=0

The zeros of -x^2+x+4=0 are x=-(-1+sqrt(17))/2 ,x=(1+sqrt(17))/2

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- x^{2} + x + 4 = 0

x = - \frac{- 1 + 17}{2}, x = \frac{1 + 17}{2}

Decimal Notation

x = - 1.56155 \dots, x = 2.56155 \dots

Solution steps

- x^{2} + x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 4}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 4 = 17

x_{1, 2} = \frac{- 1 \pm 17}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 17}{2 ( - 1 )}, x_{2} = \frac{- 1 - 17}{2 ( - 1 )}

x = \frac{- 1 + 17}{2 ( - 1 )} : - \frac{- 1 + 17}{2}

x = \frac{- 1 - 17}{2 ( - 1 )} : \frac{1 + 17}{2}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 17}{2}, x = \frac{1 + 17}{2}

\frac{12 a ^{7} b ^{4}}{15 a ^{10} b ^{3}}

25 y^{4} - x^{2}

12 = 16

1 - \frac{2 x - 1}{2} = \frac{x + 2}{5}

\frac{- 40}{5}

What are the solutions to the equation -x^2+x+4=0 ?
The solutions to the equation -x^2+x+4=0 are x=-(-1+sqrt(17))/2 ,x=(1+sqrt(17))/2
Find the zeros of -x^2+x+4=0
The zeros of -x^2+x+4=0 are x=-(-1+sqrt(17))/2 ,x=(1+sqrt(17))/2