What are the solutions to the equation 2(3-x)^2+1/2 = 5/2 ?

The solutions to the equation 2(3-x)^2+1/2 = 5/2 are x=2,x=4

Find the zeros of 2(3-x)^2+1/2 = 5/2

The zeros of 2(3-x)^2+1/2 = 5/2 are x=2,x=4

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2 (3 - x)^{2} + \frac{1}{2} = \frac{5}{2}

x = 2, x = 4

Solution steps

2 (3 - x)^{2} + \frac{1}{2} = \frac{5}{2}

Move

\frac{1}{2}

to the right side

2 (3 - x)^{2} = \frac{5}{2} - \frac{1}{2}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

2 (3 - x)^{2} = \frac{5 - 1}{2}

Subtract the numbers:

5 - 1 = 4

2 (3 - x)^{2} = \frac{4}{2}

Divide the numbers:

\frac{4}{2} = 2

2 (3 - x)^{2} = 2

Divide both sides by

2

(3 - x)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 - x = 1 : x = 2

Solve

3 - x = - 1 : x = 4

The solutions to the quadratic equation are:

x = 2, x = 4

3 x^{2} + 7 x + 2 = 0

4 x^{2} - 13 = 0

s^{2} + 4

5 x + 3 = 8

2 x - 1 < 4

What are the solutions to the equation 2(3-x)^2+1/2 = 5/2 ?
The solutions to the equation 2(3-x)^2+1/2 = 5/2 are x=2,x=4
Find the zeros of 2(3-x)^2+1/2 = 5/2
The zeros of 2(3-x)^2+1/2 = 5/2 are x=2,x=4